| Array wiring [message #22746] |
Sun, 24 July 2005 06:35  |
greenie512
Messages: 14
Registered: May 2009
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Chancellor |
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Well, finally (surface, economy) my 34 NBS arrived in Brisbane. I was talking about doing a 3/4/4/6 power taper in a thread below. Now I have to do it? could some one confirm I have the wiring configured correctly? I'm assuming within a series group I go "in" positive, "out" negative to next positive etc. Cheers - Phil
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| Re: Array wiring [message #22747 is a reply to message #22746] |
Sun, 24 July 2005 07:17  |
FredT
Messages: 704
Registered: May 2009
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Illuminati (1st Degree) |
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Your diagram is correct, but it might be simpler to wire one four-driver set as 4,5,6,7 and the other as 11,12,13,14. Each set of drivers is wired "positive in, negative out to the next positive", etc. Drivers 8-10 are located at the center of the array, with the four-driver sets located directly below and directly above the center three. The six driver set is split, with 1,2, and 3 located at one far end of the array and the 15,16,17 located at other end. The four "sets" are wired in parallel, providing a nominal impedance that's equal the impedance of the individual drivers. (Someone please correct me if any of this is wrong) This should make an awesome looking array.
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| Re: Array wiring [message #22748 is a reply to message #22747] |
Sun, 24 July 2005 16:17 |
greenie512
Messages: 14
Registered: May 2009
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Chancellor |
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Thanks Fred - your wiring suggestion is easier. I'm not sure why I decided to split/balance the sets of 4 around the centre I think you are correct and it'd be easy just to have a whole set either side and the power taper would remain the same.
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