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Re: 4 x 1 Ohm = 16 Ohms (sometimes) [message #9111 is a reply to message #9110]

Mon, 25 July 2005 23:43

Damir
Messages: 1005
Registered: May 2009

Illuminati (2nd Degree)

And how four identical 1-Ohm windings connected parallel become 4-Ohms secondary? The same for your 8-Ohms example. Can you post your math? Impedance (z) and turns ratio (n) are different things, z=n^2 - that`s why I posted it, some people are little confused...

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[Message index]

		4 x 1 Ohm = 16 Ohms (sometimes) By: Damir on Mon, 25 July 2005 15:01
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Thermionic on Mon, 25 July 2005 15:38
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Manualblock on Mon, 25 July 2005 17:01
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Damir on Tue, 26 July 2005 05:54
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: chana on Mon, 25 July 2005 20:34
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Damir on Mon, 25 July 2005 23:43
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: chana on Wed, 27 July 2005 17:27
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Damir on Tue, 26 July 2005 06:00
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Thermionic on Tue, 26 July 2005 11:53
		Re: 4 x 1 Ohm = 16 Ohms (sometimes) By: Damir on Tue, 26 July 2005 14:31

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