Simple (very) math [message #42858 is a reply to message #42855] |
Fri, 31 October 2003 11:18 |
JLapaire
Messages: 156 Registered: May 2009
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I'm going to hop in with a thought. Because the impedance of the driver loaded in a horn is higher than nominal, the amp can output a higher voltage without the driver actually seeing more power. If power dissipated = voltage squared over resistance, than an increase in resistance results in lower power. Is that about right? John
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