From the Honourable Damir:
If I understand you correctly, with self resonance f~1kHz and L~650H, we can expect: Cw = 1 / (4Pi^2 * f^2 * L) ~ 39 pF
Can you explain your results / findings in more details?
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It's too bad that half the windings don't have a quarter of the capacitance!
Half the coil has half the L, unless it's by itself...then ov course it has a quarter of the end to end L.
cheers,
Douglas