I was thinking that the middle two drivers needed to be wired in such a way as to present a load half of what the outer six drivers would present, then the other two drivers(4&7) would split the difference. So lets say that drivers 1,2,3,8,9,10 gave an 8ohm load, drivers 4,7 a 6ohm load, and drivers 5,6 a 4ohm load. This to me was a taper, and I was looking for three levels. It seems there are only two power levels in a 3/2/2/3 taper.

If I understand you correctly, drivers 1,2,3,8,9,10 will give the same load(2 sets of 12ohms each), and drivers 4,5,6,7 will also give the same load(2 sets of 8ohms each). When these are wired in parallel, there wil be a total load of 2.40 ohms. Correct?

Thank you again for your help.