L pad [message #93153] |
Sat, 20 February 2021 10:08 ![Go to next message Go to next message](/forum/theme/AudioRoundTable/images/down.png) |
johnnycamp5
Messages: 354 Registered: June 2015 Location: NJ
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Grand Master |
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I have a very elementary question for any crossover circuit experts...
I am under the impression that a single resistor in series with a loudspeaker can increase overall impedance but also alter/attenuate frequency response, where an L-pad configuration (r-1 series x r-2 parallel) will increase the impedance without changing F.R.
Is this generalization mostly correct?
I have an upcoming build where I am trying to pad down a large waveguide/CD combo (ME464/DCX464) from 111db sensitivity to 98db sensitivity (to closer match a jbl2226). Basically a two way speaker.
They will be hi-amped, so I'm not sure how critical it is, but I'd like to pad down the 8ohm compression driver anyhow to get a closer start and the additional noise floor reduction ...
I am referring to an increase in overall loudspeaker impedance to a decrease in its overall sensitivity, I'm not sure if that is correct or not.
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Re: L pad [message #93156 is a reply to message #93153] |
Sat, 20 February 2021 11:22 ![Go to previous message Go to previous message](/forum/theme/AudioRoundTable/images/up.png) ![Go to next message Go to next message](/forum/theme/AudioRoundTable/images/down.png) |
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Wayne Parham
Messages: 18748 Registered: January 2001
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Illuminati (33rd Degree) |
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That's right, exactly. A series resistor will attenuate overall SPL but will create a peak at resonance.
Look at the impedance curve of the driver. Better still, if you can, look at the impedance curve of the driver in the box, horn or whatever you have it installed in.
Wherever you see an impedance rise, SPL will be louder. So since the impedance usually has a pretty big peak at resonance - or in some installations, resonances - those will have corresponding peaks in response. It's because the voltage division changes due to the resistance changes. For example, where the driver is 8Ω and the resistor is 8Ω, the voltage is cut in half so SPL will be reduced by 6dB. But at resonance, if the driver's impedance is 80Ω, then you can see that the proportions change. The driver's impedance is 10x greater than the series attenuation, so the attenuation is almost nothing.
This is even more pronounced because of the crossover reactivity. What I said above holds true if you just had the driver installed without a crossover. But the crossover itself has reactive components that are damped by the load so that they do not become resonant. But if the load is decreased, e.g. resistance is increased, then the crossover itself will become resonant. I've seen 15dB peaks from this. Midwoofers without a Zobel sometimes have huge peaks near the crossover frequency. Horn tweeters with series resistors can have similarly large peaks near the horn's flare frequency, often times two or three of them.
Check out this document I did about 20 years ago. It shows this very well.
Some years at the Lone Star AudioFest, I do a seminar that shows this issue, illustrated with crossover diagrams and response charts. I then hook up a physical circuit and let the audience hear it, switching between a crossover that is improperly damped and another that has proper damping. It lets you actually hear this peak. I encourage you to duplicate these experiments. It's quite interesting.
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Re: L pad [message #93164 is a reply to message #93153] |
Sat, 20 February 2021 18:44 ![Go to previous message Go to previous message](/forum/theme/AudioRoundTable/images/up.png) |
johnnycamp5
Messages: 354 Registered: June 2015 Location: NJ
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Grand Master |
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I just started digging into the "crossover electronics 101 handout".
What a great read so far!
So cool when I got to the section of "damping"...
I was thinking to myself...this looks and sounds exactly like overdamped and underdamped alignments while playing with "winISD"
It ends up that's exactly what it is!!
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