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Re: Ping Wayne: Paramour noise reduction? [message #8986 is a reply to message #8985]

Tue, 24 May 2005 08:01

Wayne Parham
Messages: 18789
Registered: January 2001

Illuminati (33rd Degree)

If you add a resistor in series, then B+ will drop. The amount is determined by current flow through the resistor. You can calculate PS current draw by measuring the voltage across the resistor that's already in the circuit and using Ohms law to calculate current. Then use Ohm's law to calculate the amount of voltage drop that wil be caused by putting another resistor in the line.

Ohms law is pretty simple stuff:

E = I · R

I = E / R

R = E / I

Where E is volts, I is amps and R is ohms.

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[Message index]

		Ping Wayne: Paramour noise reduction? By: Mark Williams on Mon, 23 May 2005 13:51
		Re: Ping Wayne: Paramour noise reduction? By: Wayne Parham on Mon, 23 May 2005 17:39
		Re: Ping Wayne: Paramour noise reduction? By: Mark Williams on Mon, 23 May 2005 19:45
		Re: Ping Wayne: Paramour noise reduction? By: Wayne Parham on Mon, 23 May 2005 22:15
		Re: Ping Wayne: Paramour noise reduction? By: Mark Williams on Tue, 24 May 2005 07:54
		Re: Ping Wayne: Paramour noise reduction? By: Wayne Parham on Tue, 24 May 2005 08:01

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