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The return of the son of DN2540 CCS [message #8904 is a reply to message #8900] |
Fri, 15 April 2005 13:40 |
Damir
Messages: 1005 Registered: May 2009
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Illuminati (2nd Degree) |
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Hi, you can set the current by changing the resistance of R3 - "trimmer" pot. The best way, (as Doug explained earlier) is to use 9V battery, and connect it like on the diagram: - our CCS is Q1, Q2, R2, R4 and R3 pot - connect +pole of 9V battery to the upper mosfet drain (where you`d connect B+=200V in "Guinevere") - connect minus pole to the "anode out" of our CCS in series with 100 Ohms resistor - see the schematic - connect the voltmeter (set on about 4V range or so) between the points B & C (across 100 Ohms resistor) - you can set the P3 in the middle position, and slowly turn it on one side - the "goal" is 1,5V DC reading on our voltmeter. Ohms Law - 15mA "through" the 100 Ohms resistor is 1,5V DC voltage "drop". When you decrease the resistance - current increases, and opposite. - in my case, I get R3=100,5 Ohms for the first CCS I built, and 112,6 Ohms for the second - you can leave R5=100 Ohms in place when you install CCSs in "Guinevere" and check the current again - for more, see "Grup Build" forum, I posted new PCB
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and with Damir's fine drawing... [message #8907 is a reply to message #8904] |
Sat, 16 April 2005 18:46 |
PakProtector
Messages: 935 Registered: May 2009
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Illuminati (2nd Degree) |
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One can test in-circuit. Attach the + lead to either A or B( the same thing circuit-wise ), and the - end to ground, and set meter to mA of current. ****check the safety fuse in the meter first. If it's blown, you won't get a reading. ***the bias LED's will go out. All the regulated current will bypass the amplifier triode through the meter. regards, Douglas
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