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Compensation circuit when using active crossover [message #49180] Sun, 26 March 2006 13:35 Go to next message
ccvogel is currently offline  ccvogel
Messages: 17
Registered: May 2009
Chancellor
Wayne,

I plan to use an active crossover between the 2226 woofer and 2426/2370 horn. What would your compensation circuit look like if it didn't have to perform the crossover duties? I have your Four-Pi crossover document; do some of the values just go to zero, or is the circuit completely different?

Thanks,
Craig Vogel

Re: Compensation circuit when using active crossover [message #49185 is a reply to message #49180] Mon, 27 March 2006 08:32 Go to previous messageGo to next message
Wayne Parham is currently offline  Wayne Parham
Messages: 18783
Registered: January 2001
Illuminati (33rd Degree)

See if you have the option to configure CD compensation in the active crossover, either by jumper or setup menu. If you can, use it instead of compensation in the passive circuit.


Re: Compensation circuit when using active crossover [message #49187 is a reply to message #49180] Mon, 27 March 2006 09:50 Go to previous messageGo to next message
Larry Acklin is currently offline  Larry Acklin
Messages: 54
Registered: May 2009
Baron
The "textbook" answer from Peavey- a 6 db per octave boost, starting at 4K or so. I can get a close approximation using a graphic eq.

You can vary to taste.

Larry


Re: Compensation circuit when using active crossover [message #49188 is a reply to message #49185] Mon, 27 March 2006 10:45 Go to previous messageGo to next message
ccvogel is currently offline  ccvogel
Messages: 17
Registered: May 2009
Chancellor
Wayne,

I have a very simple active crossover - no compensation options. Any other suggestions would be appreciated.

Thanks,
ccvogel

Re: Compensation circuit when using active crossover [message #49190 is a reply to message #49187] Mon, 27 March 2006 10:50 Go to previous messageGo to next message
ccvogel is currently offline  ccvogel
Messages: 17
Registered: May 2009
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Thanks, Larry

I can use this information to build a very simple compensation circuit.

ccvogel

Re: Compensation circuit when using active crossover [message #49191 is a reply to message #49188] Mon, 27 March 2006 11:26 Go to previous messageGo to next message
Wayne Parham is currently offline  Wayne Parham
Messages: 18783
Registered: January 2001
Illuminati (33rd Degree)

If your crossover has no options, then you'll have to provide your own EQ. The curve you want has a pretty simple shape, a flat shelf from the crossover point up to 4kHz and then rising response after that.

If you don't have an equalizer, you could use a series resistor and bypass cap in line at the preamp level. That will give you the rising response part of the curve. It won't provide the flat shelf from crossover up to 4kHz, but it is a simple circuit that would be better than no compensation at all.


Re: Compensation circuit when using active crossover [message #49196 is a reply to message #49191] Mon, 27 March 2006 14:56 Go to previous messageGo to next message
ccvogel is currently offline  ccvogel
Messages: 17
Registered: May 2009
Chancellor
Thanks, Wayne.

Do you have the formulas for determining the series resistor and bypass [= parallel?] cap values? I seem to recall the the Loudspeaker Design Handbook had the formulas, but I no longer have a copy.

ccvogel

Re: Compensation circuit when using active crossover [message #49197 is a reply to message #49196] Mon, 27 March 2006 15:51 Go to previous messageGo to next message
Wayne Parham is currently offline  Wayne Parham
Messages: 18783
Registered: January 2001
Illuminati (33rd Degree)

The series resistor will be dependant on load impedance. Bypass cap is found using the capacitive reactance formula, which is Xc = 1/2πFC. I'd say go with R=100kΩ and C=400pF. Go up and down doubling or halving values 'till you get where you want to be.


Thanks [message #49198 is a reply to message #49197] Mon, 27 March 2006 16:03 Go to previous message
ccvogel is currently offline  ccvogel
Messages: 17
Registered: May 2009
Chancellor
Thanks for all your help!

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