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Exact value [message #38160 is a reply to message #38147]

Wed, 04 September 2002 01:00

vladimir4
Messages: 22
Registered: May 2009

Chancellor

Hi,
sorry form my redundant input, but when you use the approach I described below you get exactly what winisd (or other speaker cad) calculates:
Example:
Eminence Delta-12LF in 3.853 ft3 box tuned to 43Hz:
one square port 5"x5" require 5.53" length
"two" ports 2.5"x5" (same area) require 6.45" length
BECAUSE: length of one port 2.5"x5" in 3.853/"two"=1.9265 ft3 for 43Hz is 6.45"
This is exact and valid approach.
V.

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[Message index]

		physics of port tuning By: dbeardsl on Mon, 02 September 2002 00:45
		not sure what you mean... By: Sam P. on Mon, 02 September 2002 08:51
		re: By: dbeardsl on Tue, 03 September 2002 01:01
		port calcs By: vladimir4 on Tue, 03 September 2002 02:02
		Re: re: By: Adam on Tue, 03 September 2002 08:52
		multiple ports By: dbeardsl on Tue, 03 September 2002 18:40
		Exact value By: vladimir4 on Wed, 04 September 2002 01:00
		Re: physics of port tuning By: Jostein on Tue, 03 September 2002 05:28

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