10 ma max draw. [message #30183] |
Fri, 21 January 2005 09:05 |
Manualblock
Messages: 4973 Registered: May 2009
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Illuminati (13th Degree) |
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Say T; using the Hammond choke will limit us to max 10 ma per channel I believe you said. Can you say what effect that will have on the signal? Will it affect bass transients? Thanks J.R.
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Re: 10 ma max draw. [message #30185 is a reply to message #30183] |
Fri, 21 January 2005 09:50 |
PakProtector
Messages: 935 Registered: May 2009
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Illuminati (2nd Degree) |
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Hey-Hey!!!, We're venturing into an area of personal opinion and speculation. I would have to say, 'it will have an effect', that is to say, I believe that you'll be able to tell the diference if you switch them out or listen to the two side by side. How big a difference and the details of this difference are open to debate I think.I don't want to get into a position where I have to make such predictions. Some of them would require a bit of shared listening experience for purposes of establishing the vocabulary. It is a question that I don't think really has an answer at this time. regards, Douglas
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Ripple Inn [message #30194 is a reply to message #30189] |
Fri, 21 January 2005 12:59 |
PakProtector
Messages: 935 Registered: May 2009
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Illuminati (2nd Degree) |
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Hey-Hey!!!, With the 70-100 uF of capacitance and 20+ Hy of inductance, we'll be expecting about a volt or so of 120 cps ripple voltage. The active load will isolate our signal path adequately( pretty damn well actually). The added iimpedance we'd get from an additional R-C section would be detrimental IMO. The current drawn form teh supply is *NOT* constant with our use of the mu output. This is getting us the low output z, at the expense of requiring attention to the PS output z. If a resistive load weere used, a second section would be required. keep asking questions, and questiioning any and every detail, you'll not bother me in any way. regards, Douglas
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Re: Ripple Inn [message #30198 is a reply to message #30197] |
Fri, 21 January 2005 14:00 |
PakProtector
Messages: 935 Registered: May 2009
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Illuminati (2nd Degree) |
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I wil assume a few idealizations with this explanation. The primary one being that the CCS operates to deliver a constant curent to the triode we are amplifying voltage signal with. There are tww outputs, one to the plate, and the other to the load( our amplifier, and small resistor next to the mute switch in the schematic ). Since these loads will consume AC, the current delivered to the CCS will be our regulated amount + {load consumption}. The PS is going to have to deliver what is consumed by the load as ideally as is possible. The CCS will act to isolate the triode from this, but it *WON'T* be ideal. So, the better the PS can deal with a slightly variable load, the better our voltage amp will perform. It is a small 'expense' IMO, but an audibly significant one I suspect. regards, Douglas
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