Posted by Damir [ 213.202.85.118 ] on August 07, 2006 at 07:27:33:
In Reply to: New Transformer posted by manualblock on August 06, 2006 at 18:52:01:
You forgot to write ^2, but you compute it well 
Rtr = 7,5*(130/117)^2 + 3 = 12,26 Ohms
It isn`t "mine", but it is well known formula...you have it elsewere, in some tube rectifiers data, for example.
The problem is - only 130V of sec. voltage means max. 130*1,4=182V (probably less in practice) - too low...except by using voltage doubler?!
Is it 130-0-130V or just 0-130V secondary?
And another thing I didn`t quite understand from your description:
"It also has a 6v leg on the pri tied to the 6v leg on the sec with a wire to both ends. On the pri. there is a tab E also."
Is it some form of "boost/buck" voltage, or...? Any chance that you can post a picture/diagram or a better description?
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