Posted by dbeardsl on April 17, 2002 at 16:28:12

In Reply to: Re: Contemplation on combined Sensitivity(long) posted by Adam on April 17, 2002 at 16:07:59:

The volts are different cause I'm calculating sensitivity at 1 Watt.
thats why it doesn't look right.

---the system of equations
Watts = Current * Volts
Volts = Current * Resistance

---expanded solution
so Watts = Current^2 * Resistance

so Current^2 = Watts / Resistance

so Current = sqrt(Watts / Resistance)

since Volts = Current * Resistance
Volts = sqrt(Watts / Resistance) * Resistance

so Volts = sqrt(Watts * Resistance)

so 2.83V = sqrt(1W * 8) for 8 ohms.
2V = sqrt(1W * 4) for 4 ohms.

If you measure sensitivity at 2.82V/1M, then the Voltage will be the same and Wattage will be different.

• Re: but - Adam 16:30:38 04/17/02 (2)
  • (epiphany) - dbeardsl 17:01:06 04/17/02 (1)
    • Re: (epiphany) - Adam 17:37:46 04/17/02 (0)