Re: Compensation circuit when using active crossover

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Posted by Wayne Parham [ 70.234.143.103 ] on March 27, 2006 at 16:51:11:

In Reply to: Re: Compensation circuit when using active crossover posted by ccvogel on March 27, 2006 at 15:56:21:


The series resistor will be dependant on load impedance. Bypass cap is found using the capacitive reactance formula, which is Xc = 1/2πFC. I'd say go with R=100kΩ and C=400pF. Go up and down doubling or halving values 'till you get where you want to be.



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