Posted by FredT [ 24.175.116.95 ] on July 24, 2005 at 08:17:05:
In Reply to: Array wiring posted by greenie512 on July 24, 2005 at 07:35:11:
Your diagram is correct, but it might be simpler to wire one four-driver set as 4,5,6,7 and the other as 11,12,13,14. Each set of drivers is wired "positive in, negative out to the next positive", etc. Drivers 8-10 are located at the center of the array, with the four-driver sets located directly below and directly above the center three. The six driver set is split, with 1,2, and 3 located at one far end of the array and the 15,16,17 located at other end. The four "sets" are wired in parallel, providing a nominal impedance that's equal the impedance of the individual drivers. (Someone please correct me if any of this is wrong) This should make an awesome looking array.
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