Posted by Renato [ 200.218.178.58 ] on May 17, 2005 at 13:38:05:
Dears Friends,
I need impedance result more ou less, in 6 ohms, I think use below arrange:
#1
#2
#3
#4
#5
#6
Tweeter
#7
#8
#9
#10
#11
#12
Option A
===========================================================
(6,7)+(3,4,5)+(8,9,10)+(1,2,11,12) = 5,66 ohms
Option B
===========================================================
(1,2,3,4)+(5,6)+(7,8)+(9,10,11,12) = 6 ohms
Option C
===========================================================
((1,2,3)+(4,5)+(6,7)+(8,9)+(10,11,12) = 8,66 ohms
Other option ? Any problem to this configurations for 12 divres of
4ohms and what te best, and why ?
Ps. My English is to bad for write, but I read without problem.
Tks,
Renato
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